(4.54)

$\alpha =0.8+0.1945{\left(\frac{S}{D}\right)}^{0.52},$ (4.55)

(4.55)

$\beta ={\beta}_{1}-2{e}^{-0.3\frac{{\mathcal{L}}_{y}}{{\mathcal{L}}_{g}}+{\beta}_{2}},$ (4.56)

(4.56)

${\beta}_{1}=2.1+4{e}^{-0.375\frac{{\mathcal{L}}_{g}}{D}-0.1},$ (4.57)

(4.57)

${\beta}_{2}={e}^{-0.21\frac{{\mathcal{L}}_{g}}{D}+0.6}-0.57.$ (4.58)

(4.58)

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