Splineless coupling means
Abstract
In the first embodiment, the invention comprises an imperforate turbine wheel having a hub of polygonal cross-section engageable with a hollow shaft of polygonal conformation, and a thrust collar and bolt for fastening the shaft and wheel together.
- Inventors:
-
- Swampscott, MA
- (Randolph, MA)
- Issue Date:
- Research Org.:
- NORTHERN RESEARCH & ENG CORP
- OSTI Identifier:
- 864269
- Patent Number(s):
- 4340317
- Assignee:
- Northern Research & Engineering Corp. (Woburn, MA)
- Patent Classifications (CPCs):
-
F - MECHANICAL ENGINEERING F16 - ENGINEERING ELEMENTS AND UNITS F16D - COUPLINGS FOR TRANSMITTING ROTATION
F - MECHANICAL ENGINEERING F01 - MACHINES OR ENGINES IN GENERAL F01D - NON-POSITIVE DISPLACEMENT MACHINES OR ENGINES, e.g. STEAM TURBINES
- DOE Contract Number:
- AC03-79ET15426
- Resource Type:
- Patent
- Country of Publication:
- United States
- Language:
- English
- Subject:
- splineless; coupling; means; embodiment; comprises; imperforate; turbine; wheel; hub; polygonal; cross-section; engageable; hollow; shaft; conformation; thrust; collar; bolt; fastening; hollow shaft; thrust collar; turbine wheel; coupling means; polygonal cross-section; /403/416/417/
Citation Formats
Heitmann, Arnold M, and Lord, Jr., Richard E. Splineless coupling means. United States: N. p., 1982.
Web.
Heitmann, Arnold M, & Lord, Jr., Richard E. Splineless coupling means. United States.
Heitmann, Arnold M, and Lord, Jr., Richard E. Fri .
"Splineless coupling means". United States. https://www.osti.gov/servlets/purl/864269.
@article{osti_864269,
title = {Splineless coupling means},
author = {Heitmann, Arnold M and Lord, Jr., Richard E.},
abstractNote = {In the first embodiment, the invention comprises an imperforate turbine wheel having a hub of polygonal cross-section engageable with a hollow shaft of polygonal conformation, and a thrust collar and bolt for fastening the shaft and wheel together.},
doi = {},
journal = {},
number = ,
volume = ,
place = {United States},
year = {1982},
month = {1}
}