What happens if an unbroken flavor symmetry exists?

Journal Article · Sat Jan 01 00:00:00 EST 2005 · Physical Review. D, Particles Fields

DOI:https://doi.org/10.1103/PhysRevD.71.016010· OSTI ID:20705766

Koide, Yoshio ^[1]

---

1. Department of Physics, University of Shizuoka, 52-1 Yada, Shizuoka 422-8526 (Japan)

Without assuming any specific flavor symmetry and/or any specific mass-matrix forms, it is demonstrated that if an unbroken flavor symmetry exists, we cannot obtain the Cabibbo-Kobayashi-Maskawa (CKM) quark mixing matrix V and the Maki-Nakagawa-Sakata (MNS) lepton mixing matrix U except for those between two families for the case with the completely undegenerated fermion masses, so that we can never give the observed CKM and MNS mixings. Only in the limit of m{sub {nu}}{sub 1}=m{sub {nu}}{sub 2} (m{sub d}=m{sub s}), we can obtain three family mixing with an interesting constraint U{sub e3}=0 (V{sub ub}=0)

• OSTI ID: 20705766
• Journal Information: Physical Review. D, Particles Fields, Vol. 71, Issue 1; Other Information: DOI: 10.1103/PhysRevD.71.016010; (c) 2005 The American Physical Society; Country of input: International Atomic Energy Agency (IAEA); ISSN 0556-2821
• Country of Publication: United States
• Language: English

Related Subjects

72 PHYSICS OF ELEMENTARY PARTICLES AND FIELDS
FLAVOR MODEL
KOBAYASHI-MASKAWA MATRIX
LEPTONS
QUARKS
REST MASS
SYMMETRY
SYMMETRY BREAKING