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Variation of Constants? Let us recall how we solved
 

Summary: Variation of Constants?
Let us recall how we solved
(IVP).
dy
dx
+ p(x)y(x) = q(x), y(x0) = y0
First solve
d
dx
+ p(x)y(x) = 0, (x0) = 1.
(This is the reciprocal of the one we considered earlier, but it fits the current context better as we shall
see.) We calculate
d
dx
(x)-1
y(x) = -(x)-2 d
dx
y(x) + (x)-1 dy
dx
= -(x)-2

  

Source: Allard, William K. - Department of Mathematics, Duke University

 

Collections: Mathematics