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ELEC 302 HW #9: Solutions For questions, comments or typos: cosmin.ionita[at]rice.edu
 

Summary: ELEC 302 HW #9: Solutions
For questions, comments or typos: cosmin.ionita[at]rice.edu
Problem [1]. Clearly
PQ = P
1
2 P
1
2 QP
1
2 P-1
2 ,
PQ = Q-1
2 Q
1
2 PQ
1
2 Q
1
2 .
As eigenvalues are preserved under similarity transformations, it follows that the matrices PQ, P

  

Source: Antoulas, Athanasios C. - Department of Electrical and Computer Engineering, Rice University

 

Collections: Engineering