Summary: ELEC 302 HW 5: Solutions
For questions, comments or typos: cosmin.ionita[at]rice.edu
Problem [1]. (a) A =




-1 -1 -1 0
1 -1 0 0
-1 0 -1 -1
0 0 1 -1



and B =




1 0

Source: Antoulas, Athanasios C. - Department of Electrical and Computer Engineering, Rice University

Collections: Engineering