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Math 1550 Fall 2005 Section 31 P. Achar
 

Summary: Math 1550 Fall 2005
Section 31 P. Achar
Extra Credit Solution
Due: October 25, 2005
There is more than one way to find the formula. Here is a solution using logarithmic differentiation:
y = f(x)g(x)
ln y = ln f(x)g(x)
= g(x) ln f(x) (from logarithm laws)
1
y
dy
dx
= g(x)
d
dx
ln f(x) + ln f(x)
d
dx
g(x) chain rule; product rule
= g(x)

  

Source: Achar, Pramod - Department of Mathematics, Louisiana State University

 

Collections: Mathematics