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Mid-Sem Solution Maximum marks: 25 CS-681
 

Summary: Mid-Sem Solution
Maximum marks: 25 CS-681
October 3, 2003
Duration: 2 hours
Note: There are many possible ways of solving these problems. What is given here is just one (presumably
more common) way of solving them.
1. (3 marks) Number of clients to support (M) = 200
Average think-time of each client (1/) = 4 seconds
=
1
4
The system should not be saturated for 200 clients. Thus (Ref: Eq# 8.71, Trivedi 2/e):
M
= 1 +


200 = 1 + 4
=
199
4

  

Source: Apte, Varsha - Department of Computer Science and Engineering, Indian Institute of Technology Bombay

 

Collections: Computer Technologies and Information Sciences