Summary: SOLUTIONS FOR REVIEW PROBLEMS
FOR THE SECOND MIDTERM
MATH 5651, FALL 2011
INSTRUCTOR: PROF. GREG W. ANDERSON
§3.11: 4,8,9,10,18,19,22
§4.9: 5,7,8,13,18,21,24
§5.11: 2,3,6,8,9,11,18
Problem 4 of §3.11
Since fX(x) = e-|x|
/2, we have
FX(x) =



1
2
x
-
et
dt = et

Source: Anderson, Greg W. - School of Mathematics, University of Minnesota

Collections: Mathematics