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SOLUTIONS FOR REVIEW PROBLEMS FOR THE SECOND MIDTERM
 

Summary: SOLUTIONS FOR REVIEW PROBLEMS
FOR THE SECOND MIDTERM
MATH 5651, FALL 2011
INSTRUCTOR: PROF. GREG W. ANDERSON
3.11: 4,8,9,10,18,19,22
4.9: 5,7,8,13,18,21,24
5.11: 2,3,6,8,9,11,18
Problem 4 of 3.11
Since fX(x) = e-|x|
/2, we have
FX(x) =



1
2
x
-
et
dt = et

  

Source: Anderson, Greg W. - School of Mathematics, University of Minnesota

 

Collections: Mathematics